From a rifle of mass 4 kg a bullet of mass 50 gram is fired with an initial velocity of 35 meters
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mass of the rifle= m1
velocity of the rifle= v1
mass of the bullet= m2
velocity of the rifle= v2.
According to the conservation of momentum, the total momentum of a system is always equal. and the action is always equal to a reaction.
so m1×v1= m2×v2
=4kg×x=50g×35m/s.
=4kg×x= 0.05×35m/s
= x= 1.75N/4
=x= 0.44m/s
the velocity of the rifle is 0.44 m/s
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Answer:what to find
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