Question

From a rifle of mass 4 kg A bullet of mass 50 gram is fired with an initial velocity of 35 metre per second calculate the initial recoil velocity of the rifle

Answer 1

Answer:

-0.4375 m/s

Explanation:

Mass of the rifle, m₁ = 4kg

Mass of the bullet, m₂ = 50g = 0.05 kg

Recoil velocity of the rifle = v₁

Bullet is fired with an initial velocity, v₂ = 35m/s

Initially, the rifle is at rest.

Thus, its initial velocity, v = 0

Total initial momentum of the rifle and bullet system =(m₁ + m₂)v = 0

Total momentum of the rifle and bullet system after firing :

m₁v₁ + m₂v₂ = 4(v1) + 0.05 x 35 = 4v1 + 1.75

According to the law of conservation of momentum: Total momentum after the firing = Total momentum before the firing

4v₁ + 1.75 = 0

=> v₁ = -0.4375 m/s

The negative sign indicates that the rifle recoils backwards with a velocity of 0.4375 m/s.

Therefore,

Initial recoil velocity = -0.4375 m/s

Hope it helps!

Answer 2

Answer:

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