Question

From a rifle of mass 4 kg a bullet of mass 50g is fired witj velocity 35m/s. calculate the recoil velocity of the rifle​

Answer 1

Explanation:

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The rifle and the bullet make a system. Since, there is no external force acting on it the momentum of the system should be conserved.

∴m¹ u¹ + m² u² = m¹ u¹ + m² u²

$➪4 \times0 + ( \frac{50}{100} ) \times 0 = 4v + \frac{50}{1000} \times 35$

$➪4v = - \frac{35}{20}$

$➪v = \frac{35}{80}m/s$

Note:- Negative sign indicates that recoil velocity is opposite to the motion of the bullet.

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Answer 2

Given :

• Mass of rifle, m = 4 kg

• Mass of bullet, m = 50 g = 0.05 kg

• Velocity of bullet, v = 35 m/s

To find :

• Recoil velocity of the rifle

According to the question,

➞ Momentum of bullet = Mass of bullet × Velocity of bullet

➞ Momentum of bullet = 0.05 kg × 35 m/s

➞ Momentum of bullet = 1.75 kg m/s

➞ Momentum of rifle = Mass of rifle × Velocity of rifle

➞ Momentum of rifle = 4 kg × v

➞ Momentum of rifle = 4v kg m/s

.°. Momentum of bullet = Momentum of rifle

➞ 1.75 = 4v

➞ 0.4375 = v

So,the recoil velocity of the rifle is 0.4375 m/s.