Question

From a rifle of mass 4kg, a bullet of 50g is fired with an velocity of 35 m/s .calculate the initial recoil velocity of the rifle.

Answer 1

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Here's your answer!!
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Let the initial velocity of recoil of rifle be rifle
= v1

Initial mass of rifle = 4 kg
Initial momentum of rifle = 4 kg × v1

Initial mass of the bullet = 50g = 50/1000kg = 0.05 kg

Acc. to question, the initial velocity of bullet v3 = 35 m/s

∴ The initial momentum of bullet = 0.05kg × 35m/s

Now, according to the law of conservation of momentum,

Momentum of rifle = momentum of bullet

m1v1 + m2v2 = 0

m1v1 = -m2v2

∴ 4kg × v1 = -0.05 kg × 35m/s

Now, v1 = - 0.05 × 35/4 m/s = 【- 0.4375 m/s】
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Answer 2

Explanation:

Let the initial velocity of recoil of rifle be rifle

= v1

Initial mass of rifle = 4 kg

Initial momentum of rifle = 4 kg × v1

Initial mass of the bullet = 50g = 50/1000kg = 0.05 kg

Acc. to question, the initial velocity of bullet v3 = 35 m/s

∴ The initial momentum of bullet = 0.05kg × 35m/s

Now, according to the law of conservation of momentum,

Momentum of rifle = momentum of bullet

m1v1 + m2v2 = 0

m1v1 = -m2v2

∴ 4kg × v1 = -0.05 kg × 35m/s

Now, v1 = - 0.05 × 35/4 m/s = 【- 0.4375 m/s】

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