from a rifle of mass 4kg, a bullet of mass 50g is fired with an initial velocity of 35msraise-1.calculate the initial recoil velocity of the rifle?
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Answers
Mass of the rifle (m1) = 4 kg
Mass of the bullet (m2) = 50 g = 0.05 kg
Recoil velocity of the rifle = v1
A bullet is fired with an initial velocity (v2) = 35 m/s
Initially, the rifle is at rest.
Thus, its initial velocity (v) = 0
Total initial momentum of the rifle and bullet system
⇒ (m1+m2) × v = 0
The total momentum of the rifle and bullet system after firing
= m1v1 + m2v2
= (4 × v1 ) + (0.05 × 35)
= 4v1 + 1.75
According to the law of conservation of momentum
Total momentum after the firing = Total momentum before the firing
4v1 + 1.75 = 0
v1= -1.75 / 4
v1 = – 0.4375 m/s
The negative sign indicates that the rifle recoils backwards with a velocity of 0.4375 m/s.
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Answer:
let mass of rifle be m1 and mass of rifle be m2
m1= 4kg
m2= 50 g - 0.05kg
let initial velocity of the rifle be u1 and u2 be the initial velocity of bullet
u1= 0m/s
u2= 0m/s
let the final velocity of rifle i.e recoil velocity be v1 and final velocity of the bullet is V2
v1= 35 m/s
v2= ?
initial momentum= 0(4)+0(0.05) =0
final momentum 4(35)+0.05(v2) =140+0.05v2
according to law of conservation of energy,
initial momentum=final momentum
0=140+0.05 v2
-140/0.05= v2
v2= -2800m/s
v2= -2800m/snegative sign shows the recoil of gun
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Thank you hope it helps!!!
Thank you hope it helps!!!have a nice day