from a rifle of mass 4kga bullet of mass 50g is fired with an initial velocity of 35ms^-1 . calculate the initial recoil velocity of the rifle
Answers
According to formula of recoil of gun
m1u1 = m2u2 )-As momentum is
conserved
because of no external
force
4×u1 = 50/1000 × 35
u(gun)= 0.4375 m/s
Answer:
Mass of the rifle, m1= 4 kg
Mass of the bullet, m2= 50g= 0.05 kg
Recoil velocity of the rifle= v1
Bullet is fired with an initial velocity, v2= 35m/s
Initially, the rifle is at rest.
Thus, its initial velocity, v= 0
Total initial momentum of the rifle and bullet system= (m1+m2)v= 0
Total momentum of the rifle and bullet system after firing:
= m1v1 + m2v2= 0.05 — 35= 4v1 + 1.75
According to the law of conservation of momentum:
Total momentum after the firing = Total momentum before the firing 4v1 + 1.75= 0
v1= -1.75 / 4= -0.4375 m/s
The negative sign indicates that the rifle recoils backwards with a velocity of 0.4375 m/s.
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