Question

from a rifle of mass 5kg ,a bullet of mass 50 gram is fired with an initial velocity of 50 m per second.Calculate the initial recoil of the rifle​

Answer 1

Explanation:

conservation of linear momentum

when external force act on system = 0 , linear momentum of system remains constant.

I mean, initial momentum = final momentum

here mass of rifle , M = 5Kg

mass of bullet , m = 50gm = 0.05kg

initial velocity of bullet , u = 50 m/s

we have to find initial recoil velocity of rifle , U

final velocity of bullet , v = 0

final velocity of rifle , V = 0

use conservation of linear momentum,

mu+MU=mv+MVmu+MU=mv+MV

0.05 × 50 + 5 × U = m × 0 + M × 0

0.05 × 50 + 5U = 0

5U = -0.05 × 50

U = -0.5 m/s [here negative sign shows that velocity of rifle is just opposite to the bullet . yes of course it is recoil velocity ]

hence, initial velocity of refile is -0.5 m/s

Answer 2

Answer:

-0. 3 metre per second is the answer