From a rifle of mass 5kg a bullet of mass 50g is fired with an initial velocity 60m/s of recoil of the rifle is: 1 (a) 0.8m/s (b) 0.6m/s (c) 0.9m/s (d) 1.0m/s
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you know about \text{\underline{conservation of linear momentum}}
conservation of linear momentum
when external force act on system = 0 , linear momentum of system remains constant.
I mean, initial momentum = final momentum
here mass of rifle , M = 5Kg
mass of bullet , m = 50gm = 0.05kg
initial velocity of bullet , u = 50 m/s
we have to find initial recoil velocity of rifle , U
final velocity of bullet , v = 0
final velocity of rifle , V = 0
use conservation of linear momentum,
mu+MU=mv+MVmu+MU=mv+MV
0.05 × 50 + 5 × U = m × 0 + M × 0
0.05 × 50 + 5U = 0
5U = -0.05 × 50
U = -0.5 m/s [here negative sign shows that velocity of rifle is just opposite to the bullet . yes of course it is recoil velocity ]
hence, initial velocity of refile is -0.5 m/s
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