Question

From a rifle of mass 5kg, a bullet of mass 50gram is fired with an initial velocity of 50m/s. Calculate the initial recoil velocity of the rifle.

Answer 1

you know about ..
conservation of linear momentum

when external force act on system = 0 , linear momentum of system remains constant.

I mean, initial momentum = final momentum

here mass of rifle , M = 5Kg

mass of bullet , m = 50gm = 0.05kg

initial velocity of bullet , u = 50 m/s

we have to find initial recoil velocity of rifle , U

final velocity of bullet , v = 0

final velocity of rifle , V = 0

use conservation of linear momentum,

mu+MU=mv+MVmu+MU=mv+MV

0.05 × 50 + 5 × U = m × 0 + M × 0

0.05 × 50 + 5U = 0

5U = -0.05 × 50

U = -0.5 m/s [here negative sign shows that velocity of rifle is just opposite to the bullet . yes of course it is recoil velocity ]

hence, initial velocity of refile is -0.5 m/s



ADDITIONAL....
CONSERVATION OF MOMENTUM....
 ✔✔conservation of momentum is a fundamental concept of physics along with the conservation of energy and theconservation of mass. ✔✔✔Momentum is defined to be the mass of an object multiplied by the velocity of the object

Answer 2

Hey mate here is the correct answer......

You know about ..

conservation of linear momentum

when external force act on system = 0 , linear momentum of system remains constant.

I mean, initial momentum = final momentum

here mass of rifle , M = 5Kg

mass of bullet , m = 50gm = 0.05kg

initial velocity of bullet , u = 50 m/s

we have to find initial recoil velocity of rifle , U

final velocity of bullet , v = 0

final velocity of rifle , V = 0

use conservation of linear momentum,

mu+MU=mv+MVmu+MU=mv+MV

0.05 × 50 + 5 × U = m × 0 + M × 0

0.05 × 50 + 5U = 0

5U = -0.05 × 50

U = -0.5 m/s [here negative sign shows that velocity of rifle is just opposite to the bullet . yes of course it is recoil velocity ]

hence, initial velocity of refile is -0.5 m/s

I hope it will be helpful to you......Ayush

Please mark me as BRAINLIEST ❤❤❤❤....