From a rifle of mass 5kg,a bullet of mass 80g is fired with an initial velocity of 35m/s. Calculate the initial recoil velocity of the rifle
Answers
Answer:
Initially, the rifle is at rest.
Thus, its initial velocity (v) = 0
The total initial momentum of the rifle and bullet system
⇒ (m1+m2) × v = 0
The total momentum of the rifle and bullet system after firing
= m1v1 + m2v2
= (4 × v1 ) + (0.05 × 35)
= 4v1 + 1.75
According to the law of conservation of momentum
Total momentum after the firing = Total momentum before the firing
4v1 + 1.75 = 0
v1= -1.75 / 4
v1 = – 0.4375 m/s
The negative sign indicates that the rifle recoils backwards with a velocity of 0.4375 m/s.
Explanation:
Answer:
Given
Mass of the rifle (m₁) = 4 kg
Mass of the bullet (m2)= 50 g = 0.05 kg
Recoil velocity of the rifle = V₁
A bullet is fired with an initial velocity (v2) = 35 m/s
Find out
The initial recoil velocity of the rifle
Solution
Initially, the rifle is at rest.
Thus, its initial velocity (v) = 0
The total initial momentum of the rifle and bullet system
(m₁+m2) x v = 0
The total momentum of the rifle and bullet system after firing
=m₁v₁ + m2v2
= 4v1 +1.75
According to the law of conservation of momentum
Total momentum after the firing = Total momentum before the firing
X
4v₁ +1.75 = 0
= 4v1 +1.75
According to the law of conservation of momentum
Total momentum after the firing = Total momentum before the firing4v₁ +1.75 = 0V₁=-1.75/4
V₁ = 0.4375
=4v1 + 1.75
According to the law of conservation of momentum
Total momentum after the firing = Total momentum before the firing
4v₁ +1.75 = 0
V₁=-1.75/4
V₁ = 0.4375 m/s
The negative sign indicates that the rifle recoils backwards with a velocity of 0.4375 m/s.