from a rifle of mass 7kg a bullet of mass 200 gram is fired with initial velocity 35m/s the recoil velocity of rifle will be
Answers
Answer:
Type Your Question
open sidebar
camera-retro-copy
Click Question to Get Free Answers
navigate-next
Watch 1 minute video
question-mark-1
Question From class 9 Chapter FORCE AND LAWS OF MOTION
From a rifle of mass
, a bullet of mass
is fired with an initial velocity of
. Calculate the initial recoil velocity of the rifle.
like-icon
11.5k LIKES
view-icon
15.7k VIEWS
share-icon
15.7k SHARES
check-circle
Text Solution
Solution :
We will first calculate the momentum of bullet and of the rifle separately and then apply the law of conservation of momentum. <br> (i) Momentum of bullet=Mass of bullet
Velocity of bullet <br>
<br>
<br>
.....(1) <br> (ii) Suppose the recoil velocity of the rifle is v
. So, <br> Momentum of rifle=Mass of rifle
Velocity of rifle <br>
<br>
<br> Now, according to the law of conservation of momentum: <br> Momentum of bullet=Momentum of rifle <br> So, 1.75=4v <br> And
<br>
<br> Thus, the recoil velocity of the rifle is 0.4375 metres per second.
Explanation:
I think my answer is correct pls mark as brainlist and pls follow me
Explanation:
Mass of the rifle (m1) = 4 kg
Mass of the bullet (m2) = 50 g = 0.05 kg
Recoil velocity of the rifle = v1
A bullet is fired with an initial velocity (v2) = 35 m/s
Initially, the rifle is at rest.
Thus, its initial velocity (v) = 0
Total initial momentum of the rifle and bullet system
⇒ (m1+m2) × v = 0
The total momentum of the rifle and bullet system after firing
= m1v1 + m2v2
= (4 × v1 ) + (0.05 × 35)
= 4v1 + 1.75
According to the law of conservation of momentum
Total momentum after the firing = Total momentum before the firing
4v1 + 1.75 = 0
v1= -1.75 / 4
v1 = – 0.4375 m/s
The negative sign indicates that the rifle recoils backwards with a velocity of 0.4375 m/s.
I HAVE GIVEN ANOTHER SOLUTION BUT THE QUESTION IS THE SAME ONLY THE SIGITS ARE DIFFERENT .YOU TRY TO MAKE IT YOURSELF USING YOUR VALUES OF THE QUESTION .