Question

From a right circular cylinder with height 10
cm and radius of base 6 cm a right circular
cone of the same height and base is removed.
Find the volume of the remaining solid.​

Answer 1

Answer:

1130.4 cm3

Step-by-step explanation:

h = 10 cm

r = 6 cm

v = ?

so,

v =

$\pi\:r ^{2} h$

v = 3.14 × 6^2 × 10

v = 1130.4 cm3

Answer 2

Solution:

Given:

=> Radius of base of solid cylinder, r = 6 cm.

=> Height of cylinder, h = 10 cm.

To Find:

=> Volume of remaining solid.

Formula used:

$\sf{\implies Volume\;of\;cylinder=\pi r^{2}h}$

$\sf{\implies Volume\;of\;cone=\dfrac{1}{3} \pi r^{2}h}$

Now,

$\sf{\implies Volume\;of\;cylinder=\pi r^{2}h}$

=> π (6)² (10)

=> 360 π cm³

Now, a right circular cone of same base and same height is removed from the cylinder. So,

Radius base of cone, r = 6 cm.

Height of cone, h = 10 cm

Now,

$\sf{\implies Volume\;of\;cone=\dfrac{1}{3} \pi r^{2}h}$

=> 1/3 × 360 π

=> 120 π cm³

Now, volume of remaining solid = volume of cylinder - volume of cone.

=> 360 π cm³ - 120 π cm³

=> 240 π cm³  

=> 240 × 22/7

=> 754.29 cm³

So, the volume of remaining solid = 754.29 cm³