Question

From a right circular cylinder with height
10 cm and radius of base 6 cm, a right
circular cone of the same height and base
is removed. Find the volume of the
remaining solid.
​

Answer 1

Answer:

height=10 cm

radius=6cm

volume of cylinder = πr^2h

= 3.14*6^2*10

=1884p

Answer 2

Answer:

$\tt\implies \: \boxed{ \blue{\bf \: Volume_{(remaining \: solid)} = 754.28 \: {cm}^{2} }}$

Step-by-step explanation:

We have,

☆ Height of solid circular cylinder = 10cm

☆ Radius of the base = 6cm

☆ Now, since cone of same radius and same height as of cylinder is removed, therefore

$\tt \: Volume_{(remaining \: solid)} = Volume_{(cylinder)} - Volume_{(cone)}$

$\tt \:  \longrightarrow \: Volume_{(remaining solid)} = \pi \: {r}^{2} h - \dfrac{1}{3} \pi \: {r}^{2} h$

$\tt \:  \longrightarrow \: Volume_{(remaining \: solid)} = \dfrac{2}{3} \pi \: {r}^{2} h$

$\tt \:  \longrightarrow \: Volume_{(remaining \: solid)} = \dfrac{2}{3} \times \dfrac{22}{7} \times 6 \times 6 \times 10$

$\tt \:  \longrightarrow \: Volume_{(remaining \: solid)} = \dfrac{5280}{7}$

$\tt\implies \: \boxed{ \purple{\bf \: Volume_{(remaining \: solid)} = 754.28 \: {cm}^{2} }}$