Question

from a rope 11m long ,two piece's of length 2 whole 3/5m and 3 whole 3/10m are cut off.What is the length of remaining rope?​

Answer 1

Step-by-step explanation:

Here I have done the LCM.

So pls don't confuse

Answer 2

Given:

• From a rope 11 m long
• Two piece's of length 2 whole 3/5m and 3 whole 3/10m

To Find:

• The length of remaining rope

Solution:

length of remaining rope

$=11 - (\frac{23}{5} + 3 \frac{3}{10} ) \\ \\ = 11 - ( \frac{13}{5} + \frac{33}{10}) \\ \\ = 11 - ( \frac{26 + 33}{10} ) \: \\ \\ = 11 - \frac{59}{10} \\ \\=\frac{110 - 59}{10}\\ \\ = \frac{51}{10}\\ \\ = 5 \frac{1}{10}$