Question

From a rope 11m long, two pieces of lengths 2 3/5 m and 3 3/10 m are cut off. what is the length of the remaining rope​

Answer 1

Given

Total length of the rope = 11 m

If the rope is cut into 3 pieces

Length of the first piece = 2 3/5 = 13/5m

Length of the second piece = 3 3/10=33/10 m

We have to find out length of the third piece = x

x = total length -(length of the first piece + length of the second piece)

= 11 - (13/5+33/10)

= 11-[(26+33)/10]

= 11/1 - 59/10

= (110-59)/10

= 51\10

= 5 1/10 m

Therefore, Length of the remaining piece = x = 5 1/10 m

Answer 2

Answer:

Step-by-step explanation:

Given,

Length of a rope = 11 m

Length of the two cut off pieces = 2 3/5 m and 3 3/10 m

= 13 /5 m and 33 /10 m

Sum of the two cut off pieces = 13 /5 + 33 /10 = 26 + 33 / 10 = 59 / 10 m

∴ The length of remaining rope = 11 - 59 /10 = 110 - 59 / 10 = 51 / 10 m.