from a rope 11m long,two pieces of lengths 2 3/5m and 3 3/10m are cut off. what is the length of the remaining rope?
Answers
Answered by
28
2 3/5 = 13/5 m and 3 3/10 = 33/10 m
length of remaining rope = 11-13/5 - 33/10 = 51/10 m
= 5.1 m
length of remaining rope = 11-13/5 - 33/10 = 51/10 m
= 5.1 m
saaloni:
you explained very nicely ,thank u
Answered by
50
Length of rope = 11m
Length of first piece = 2 3/5 m = 13/5 m
Length of second piece = 3 3/10m = 33/10 m
length of remaining piece =
11 - 13/5 - 33/10
= (110 - 26 - 33)/10
= (110 - 59)/10
= 51/10
= 5.1 m
Answer - Length of remaining piece is 5.1m
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Length of first piece = 2 3/5 m = 13/5 m
Length of second piece = 3 3/10m = 33/10 m
length of remaining piece =
11 - 13/5 - 33/10
= (110 - 26 - 33)/10
= (110 - 59)/10
= 51/10
= 5.1 m
Answer - Length of remaining piece is 5.1m
_________________________________________________________
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