From a rope 12 m long, two pieces of length 13/5 m and 33/10 m are cut off. What is the length of the remaining rope?
Answers
Answer:
length of rope = 12m
two pieces of length = 13/5 and 33/10 m
remaining rope = length of rope - (addition of two pieces)
=12 -(13/5+33/10)
=12-5.9 m
remaining rope = 7. 1 m
Step-by-step explanation:
Given:-
From a rope 12 m long, two pieces of length 13/5 m and 33/10 m are cut off.
To find:-
What is the length of the remaining rope?
Solution:-
Given that
Total length of the rope = 12 m
If it is cut into two pieces then
Length of the one piece = 13/5 m
Length of the other piece = 33/10 m
Total length of the two pieces
= (13/5)+(33/10)
LCM of 5 and 10 = 10
=> [(13×2)+(33×1)]/10
=> (26+33)/10
=> 59/10 m
Total length of the two pieces = 59/10 m
Remaining piece = Total length of the rope - Total length of the cutting pieces
= 12 -(59/10)
= [(12×10)-59]/10
= (120-59)/10
= 61/10
= 6.1 m
Alternative Method:-
Given that
Total length of the rope = 12 m
If it is cut into two pieces then
Length of the one piece = 13/5 m
Length of the other piece = 33/10 m
Length of the remaining piece
= 12 -[(13/5)+(33/10)]
= 12-[(26+33)/10]
= 12-(59/10)
= 12-5.9
= 6.1 m
Answer:-
The length of the remaining piece of the rope is 6.1 m