From a rope 15 m long , 13/3 m is cut off and 3/5 of the remaining is cut off again . Find the length of the remaining part of the rope .
Answers
Answered by
30
15 - 13/3 - (15-13/3)3/5
(45-13)/3-(45-13)/3*3/5
32/3-32/5
LCM of 3 and 5 is 15
32*5-32*3/15
64/15
(45-13)/3-(45-13)/3*3/5
32/3-32/5
LCM of 3 and 5 is 15
32*5-32*3/15
64/15
Answered by
58
Given,
A rope of length 15 m
13/3 m is cut off, and 3/5 of the remaining part of rope is cut off again.
To find,
Length of the remaining rope
Main Solution :
Total length of rope = 15 m
Length of rope cut off = 13/3m
Rope left = Total length of rope - length of rope cut off
=15- m
= m
= m. (i)
Now, 3/5 of this remaining rope was cut off.
Rope cut off from the remaining part = (ii)
=
Rope remaining = (i) - (ii)
= - .
= m
= m
A rope of length 15 m
13/3 m is cut off, and 3/5 of the remaining part of rope is cut off again.
To find,
Length of the remaining rope
Main Solution :
Total length of rope = 15 m
Length of rope cut off = 13/3m
Rope left = Total length of rope - length of rope cut off
=15- m
= m
= m. (i)
Now, 3/5 of this remaining rope was cut off.
Rope cut off from the remaining part = (ii)
=
Rope remaining = (i) - (ii)
= - .
= m
= m
TheLostMonk:
nice ..explaination
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