From a rope 31/2 m long three pieces of length 7/5m , 8/3m and 41/9 m are cut off what is the length of the remaining rope.
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A; from 31/2m long rope is there
the three pieces are left
then 7/5,8/3,41/9
the Lcm of 5,3,9=45
7*9+8*15+41*5/45
63+120+205/45
388/45m
31/2-388/45
the Lcm of 45,2 is 90
31*45-388*2/90
1395-776/90
619/90
6.8
then 68/10 is present
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