From a rope 75 meter long pieces of equal size are cut,each measuring 7/2 meters.How many pieces are cut off and what fraction is left?
Answers
Answered by
2
size of rope= 75 m
each have 7/2 m
then no cut piece = 75/7/2
75×2/7
= 21.42 m
Answered by
1
Solution :-
Length of rope = 75 m
Length of each piece = 7/2 m
No. of pieces cut off = ?
Fraction left out = ?
.
. . No. of pieces = 75 ÷ 7/2
= 75 × 2/7
= 150/7
= 21 ; 3/7
.
. . No. of pieces = 21
Fraction left out = 3/7 m.
Similar questions