Math, asked by NOTYOU01, 10 months ago

From a rope of 11 m long, two pieces of lengths 135 m and 3310 m are cut off. What is the length of the remaining rope?

Answers

Answered by Anonymous
4

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★ First of all, try to get a common multiple on the denominator of both the fractions to make it easier for you to add both the lengths.

★ So 13/5 both numerator and denominator is multiplied by 2 to get the denominator as 10 , which equals 26/10

★ Now 26/10 rope piece and the other rope piece 33/10 both have the same denominator, so when added .

26/10 + 33/10 = 59/10,

So 59/10 meters(5.9M) of rope has been cut off, now subtract this length from 11 meters initial rope length.

So 11 M - 5.9 M = 5.1 M remaining

or 11 x 10/10 = 110/10

110/10 - 59/10 = 51/10 (5.1)

However you do it the answer will be 5.1 Meters

Answered by Juveri08
0

Answer:

1. Try to get a common denominator of both the fractions to make it more easier to add both the lengths

2. So both 13/5 both numerator and denominator is multiplied by 2 to get the denominator as 10 Therefore 26/10

3. Now 26/10 rope piece and the other rope piece 33/10 both have the same denominator

Whe we add it

26/10 + 33/10 = 59/10

When we convert it it is 5.9 meters of rope has been cut off now subtract it from 11 M of the intial rope

So 11 M - 5.9 M = 5.1 Meter remaining or 11×10/10 =110/10

110/10 - 59/10 =51/10 (5.1)

Final Answer = 5.1 Meters

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