From a rope of 11 m long, two pieces of lengths 135 m and 3310 m are cut off. What is the length of the remaining rope?
Answers
★ First of all, try to get a common multiple on the denominator of both the fractions to make it easier for you to add both the lengths.
★ So 13/5 both numerator and denominator is multiplied by 2 to get the denominator as 10 , which equals 26/10
★ Now 26/10 rope piece and the other rope piece 33/10 both have the same denominator, so when added .
26/10 + 33/10 = 59/10,
So 59/10 meters(5.9M) of rope has been cut off, now subtract this length from 11 meters initial rope length.
So 11 M - 5.9 M = 5.1 M remaining
or 11 x 10/10 = 110/10
110/10 - 59/10 = 51/10 (5.1)
However you do it the answer will be 5.1 Meters
Answer :-
First of all, try to get a common multiple on the denominator of both the fractions to make it easier for you to add both the lengths.
- So 13/5 both numerator and denominator is multiplied by 2 to get the denominator as 10 , which equals 26/10
- Now 26/10 rope piece and the other rope piece 33/10 both have the same denominator, so when added .
- 26/10 + 33/10 = 59/10,
- So 59/10 meters(5.9M) of rope has been cut off, now subtract this length from 11 meters initial rope length.
So 11 M - 5.9 M = 5.1 M remaining
or 11 x 10/10 = 110/10
110/10 - 59/10 = 51/10 (5.1)
However you do it the answer will be 5.1 Meters