Math, asked by seemajhadbg87, 8 months ago

From a rope of 11m long, two pieces of lengths 2.3/5m and 3.3/10 m are cut off. what is the length of the remaining rope?​

Answers

Answered by zainabulbannah
0

Answer:

11-(2.3/5+3.3/10) =remaining rope

Step-by-step explanation:

11-0.79=10.21

The remaining length is therefore 10.21m

Answered by omgullushankar123456
2

Answer:

10.21m

Step-by-step explanation:

total meter of rope =11 m

length of one piece of rope =2.3÷5m

length of second piece = 3.3 ÷10 m

so, the remaining rope

= 11-(2.3/5+3.3/10)

= 11-7.9/10

= 1021/100

= 10.21 m

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