Question

From a rope of 13m long, two pieces of length 10/6 & 15/7 cut off. The length of remaining rope is

Answer 1

Answer:

Total length of the rope = 13 m

Out of which cut off = ( $\frac{10}{6}$ + $\frac{15}{7}$ ) m

                                 = ($\frac{5}{3}$ + $\frac{15}{7}$ ) m        [ After cancelling it ]

                                 = $\frac{35 + 45}{21}$ m

                                 = $\frac{80}{21}$ m

The remaining length of the rope = 13 - $\frac{80}{21}$ m

                                                       = ( $\frac{273-80}{21}$ ) m

                                                      $\frac{193}{21}$ m

   Thank you.