Question

from a rope of length 20 whole 1 by 2 m a piece of length 5 whole 2 by 5 m find the total weight of the remaining rope ​

Answer 1

Answer:

Total length of rope =20

2

1

m

Length cut off =3

8

5

Remaining rope=[20

2

1

−3

8

5

]m

=[

2

41

−

8

29

]m

2 ∣2,8

4 ∣1,4

∣1,1

∴ LCM of 2 and 8 is 8

=

8

41×4−29×1

[

8

164−29

]m

=[

8

135

]m=16

8

7

m

∴Length of the remaining rope =16

8

7

m

Step-by-step explanation:

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