Math, asked by avani413, 2 months ago

from a set of 12 cards numbered 1 2 3 4 5 6 7 8 9 10 11 12 is drawn what is the probability of probability that its number is a multiple of 3​

Answers

Answered by grithachinnu86
1

Answer:

Since, total cards = 15

(i)  total odd no.'s from 1 to 15 = 8

    ∴ favorable outcomes= 8

   ∴ probability = 158

(ii) Total Multiples of 4 from 1 to 15 = 3

     ∴ favorable outcomes= 3

     ∴ probability = 153=51

(iii) Total no's divisible by 5 from 1 to 15 = 3

     ∴ favorable outcomes= 3

    ∴ probability = 153=51

(iv) Total no's divisible by 2 and 3 from 1 to 15 are:

       6,12

       ∴ favorable outcomes= 2

    ∴ probability = 152

(v) Total no's less than or equal to 10 from 1 to 15 = 10

     ∴ favorable outcomes= 10

    ∴ probability = 1510=32

hope it helps you pls mark me as brain list pls pls pls

Answered by atheranasabbas
1

Answer:

Mark me the brainliest

Step-by-step explanation:

total no of cards -12

multiple of 3 -3,6,9,12 (4 numbers)

therefore (p) of getting a multiple of 3 is : 4/12

simplify : 1/3

Similar questions