Question

from a ships masthead 25m high, the angle of depression of a boat is observed to be 60°.find the distance of the boat from the ship.​

Answer 1

Answer

AnswerOpen in answr app

AnswerOpen in answr appCorrect option is

AnswerOpen in answr appCorrect option isC

AnswerOpen in answr appCorrect option isC50(3−1)m

AnswerOpen in answr appCorrect option isC50(3−1)mConsider the above given figure

AnswerOpen in answr appCorrect option isC50(3−1)mConsider the above given figureLet AB be the mast of the ship and DC be the distance between the boats

AnswerOpen in answr appCorrect option isC50(3−1)mConsider the above given figureLet AB be the mast of the ship and DC be the distance between the boatsConsider triangle ABC

AnswerOpen in answr appCorrect option isC50(3−1)mConsider the above given figureLet AB be the mast of the ship and DC be the distance between the boatsConsider triangle ABC∠ACB=450

AnswerOpen in answr appCorrect option isC50(3−1)mConsider the above given figureLet AB be the mast of the ship and DC be the distance between the boatsConsider triangle ABC∠ACB=450Therefore, ∠ABC=450

AnswerOpen in answr appCorrect option isC50(3−1)mConsider the above given figureLet AB be the mast of the ship and DC be the distance between the boatsConsider triangle ABC∠ACB=450Therefore, ∠ABC=450Hence triangle ABC is a an isosceles triangle. 

AnswerOpen in answr appCorrect option isC50(3−1)mConsider the above given figureLet AB be the mast of the ship and DC be the distance between the boatsConsider triangle ABC∠ACB=450Therefore, ∠ABC=450Hence triangle ABC is a an isosceles triangle. Therefore AB=AC=50 m

AnswerOpen in answr appCorrect option isC50(3−1)mConsider the above given figureLet AB be the mast of the ship and DC be the distance between the boatsConsider triangle ABC∠ACB=450Therefore, ∠ABC=450Hence triangle ABC is a an isosceles triangle. Therefore AB=AC=50 mConsider triangle ABD,

AnswerOpen in answr appCorrect option isC50(3−1)mConsider the above given figureLet AB be the mast of the ship and DC be the distance between the boatsConsider triangle ABC∠ACB=450Therefore, ∠ABC=450Hence triangle ABC is a an isosceles triangle. Therefore AB=AC=50 mConsider triangle ABD,tan300=31

AnswerOpen in answr appCorrect option isC50(3−1)mConsider the above given figureLet AB be the mast of the ship and DC be the distance between the boatsConsider triangle ABC∠ACB=450Therefore, ∠ABC=450Hence triangle ABC is a an isosceles triangle. Therefore AB=AC=50 mConsider triangle ABD,tan300=31=ADAB=50+CD50