Question

from a solid circular cylinder with height 10cm and radius of base is 6cm, a right circular cone of same height and same base is removed. find the volume of remaining solid. also calculate the whole surface area​

Answer 1

Answer:

that

is

the

correct

answer

Answer 2

Answer:

Area of cylinder =

$2\pi \times r \: (r + h)$

$2 \times \binom{22}{7} \times 6 \times (6 + 10)$

$2 \times \binom{22}{7} \times 6 \times 16$

$4224 \div 7$

603.4286

≈603.43 sqcm

$l = \sqrt{ {r }^{2} + {h}^{2} }$

$l = \sqrt{ {6}^{2} + {10}^{2} }$

$l = \sqrt{136}$

$l = 11.66 \: cm$

Area of cone =

$\pi \times r (r + l)$

$\binom{22}{7} \times 6(6 + 11.66)$

$\binom{22}{7} \times 6 \times 17.66$

$\binom{2331.12}{7}$

Area of cone = 333.017

Area of cone ≈ 333.02 sqcm

Area of remaining part = Area of cylinder - Area of cone

Area of remaining part = 603.43 -333.02

Area of remaining part = 270.41 sqcm