from a solid circular cylinder with height 10cm and radius of the base 6cm a right circular cone of the same height and same base is removed then the volume of remaining solid is
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Answer:
volume of cylinder=π×(6^2)×10
volume of cone=(1/3)π(6^2)×10
volume of the remaining=π(6^2)10-(1/3)π(6^2)10
=(2/3)π(6^2)10
=2×22×36×10/(3×7)
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