Question

From a solid circular cylinder with height 10cm and radius of the base 6cm,a right circular cone of the same height and same base is removed. Find the volume of the remaining solid.Also, find the whole surface area.

#Please give correct answer.

Answer 1

I hope it helps mate

Answer 2

Given, Height of cylinder h = 10 cm.

Given, Radius of the base = 6 cm.

It is given that a right circular cone of the same height and same base is removed.

Required volume = Volume of cylinder - Volume of cone

⇒ πr²h - (1/3)πr²h

⇒ (22/7) * (6)² * 10 - (1/3) * (22/7) * (6)² * 10

⇒ (22/7)[360 - 120]

⇒ (22/7)[240]

⇒ 754.28 cm³ (or) 754.3 cm³.

Now,

We know that slant height (l) = √r^2 + h²

⇒ √6^2 + 10²

⇒ √136

⇒ 2√34

⇒ 11.66

Total surface area = (2πrh + πr² + πrl)

⇒ (2 * 22/7 * 6 * 10 + 22/7 * 6² + 22/7 * 6 * 11.66)

⇒ (22/7)[2 * 60 + 36 + 69.96]

⇒ (22/7)[225.96]

⇒ 710.6 cm²

Therefore:

⇒ Volume of the remaining solid = 754.28 (or) 754.3 cm³

⇒ Whole surface area = 710.6 cm².

Hope it helps!