From a solid circulars cylinder with height 12cm and radius of the base 5cm,a right circular cone of same height and the same base radius is removed.find the volume and total surface area of the remaining solid.
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Answer:
cylinder
h=12 cm
R=5cm
cone
h=12cm
r=5cm
volume of remaining solid
=πr²h -1/3πr²h
πr²h(1-1/3)
=22/7 x 25 x 12 x 2/3 = 628.5 cm³
tsa = 2πrh+πr²+πrl
l=√12²+5² =√169=13cm
πr(2h+r+l)=22/7 x 5 x (24+5+13) =660 cm²
Step-by-step explanation:
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