From a solid cylinder of height 14cm and base diameter 7 CM two equal conical holes each of radius 2.1 CM and height 4cm are cut off.Find the volume of remaining solid
Answers
Answered by
338
Volume of cylinder= π×r×r×h
=22/7×3.5×3.5×14
=539 sqcm
Volume of conical holes=1/3π×r×r×h
=1/3×22/7×2.1×2.1×4
=18.48 sqcm
There are two conical holes so
2×18.48
=36.96 sqcm
So remaining volume= 539 - 36.96
=502.04 sqcm
=22/7×3.5×3.5×14
=539 sqcm
Volume of conical holes=1/3π×r×r×h
=1/3×22/7×2.1×2.1×4
=18.48 sqcm
There are two conical holes so
2×18.48
=36.96 sqcm
So remaining volume= 539 - 36.96
=502.04 sqcm
Answered by
112
h= 7cm
r=2.1cm
d=7cm
volume=πr^2h
22/7×3.5×3.5×14
539 cm^2
volume of colonial holes=1/3πr^2h
1/3×22/7×2.1×2.1×4
18.48 cm^2
there are two colonial holes=2×18.48
36.96 cm^2
so remaining volume=539×36.96
502.04 cm^2
r=2.1cm
d=7cm
volume=πr^2h
22/7×3.5×3.5×14
539 cm^2
volume of colonial holes=1/3πr^2h
1/3×22/7×2.1×2.1×4
18.48 cm^2
there are two colonial holes=2×18.48
36.96 cm^2
so remaining volume=539×36.96
502.04 cm^2
Similar questions