From a solid cylinder of height 30cm and radius 7cm, conical cavity of height 24cm and of base radius 7cm is drilled out. Find the volume and the total surface of the remaining solid
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Step-by-step explanation:
- Given
- height of the cylinder, H = 30 cm
- Radius of the cylinder, r = 7 cm
- Height of cone, h = 24 cm
- Radius of cone, r = 7 cm
- Slant height of the cone, l = √(h2+r2)
l = √(242+72)
l = √(576+49)
l = √(625)
l = 25 cm
- Volume of the remaining solid = Volume of the cylinder – Volume of the cone
= r2H – (1/3)r2h
= r2(H- h/3)
= (22/7)×72×(30-24/3)
= (22×7)×(30-8)
= (154)×(22)
= 3388 cm3
Volume of the remaining solid is 3388 cm3.
- Total surface area of the remaining solid = Curved surface area of cylinder + surface area of top of the cylinder+ curved surface area of the cone
Total surface area of the remaining solid = 2rH + r2 + rl
= r(2H + r + l)
=(22/7)×7(2×30 + 7+ 25)
= 22×(60+32)
= 22×92
= 2024 cm2
Hence the total surface area of the remaining solid is 2024 cm2.
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