From a solid cylinder of height 7 cm and base diameter 12cm,a conical cavity of same height and smae base diameter is hollowed out. Find the total surface area of the remaining solid upto two decimal places. [Take root 85 =9.2]
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h=7cm
d=12
r=12/2
=6cm
T.S.A of cylinder=2×3.14×6×6+7
=488.84cm2
l=36+49(root)
l=85(root)
l=9.2(A.T.Q)
Now,
T.S.A of cone=3.14×6(9.2+6)
=29.3904cm2
T.S.A of remaining Solid= T.S.A of cylinder-T.S.A of cone
488.85-29.3904
=459.4596cm2
Hope you understood.......:)
d=12
r=12/2
=6cm
T.S.A of cylinder=2×3.14×6×6+7
=488.84cm2
l=36+49(root)
l=85(root)
l=9.2(A.T.Q)
Now,
T.S.A of cone=3.14×6(9.2+6)
=29.3904cm2
T.S.A of remaining Solid= T.S.A of cylinder-T.S.A of cone
488.85-29.3904
=459.4596cm2
Hope you understood.......:)
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