Question

From a solid cylinder of height 7 cm and base diameter of 12 cm, a conical cavity of same height and same base diameter is hollowed out. Find the total surface area of the remaining solid. (Use 7
22
π 

Answer 1

Answer: 554.568 cm^2 is the correct answer

Step-by-step explanation:

Answer 2

528 cm³

Step-by-step explanation:

Dimensions of cylinder:

⠀⠀Height of cylinder = h = 7 cm

⠀⠀Radius of cylinder = r = 6 cm

Dimensions of cone:

⠀⠀Radius of cone = r = 6 cm

⠀⠀Height of cone = h = 7 cm

As , Volume of cone = $\rm \dfrac{1}{3}\pi r^2 h$, Volume of cylinder = $\rm \pi r^2 h$

Hence, volume of remaining portion,

$\rm :\longmapsto V = \pi r^2 h - \dfrac{1}{3}\pi r^2h$

$\rm :\longmapsto V = \dfrac{2}{3} \pi r^2h$

$\rm :\longmapsto V = \dfrac{2}{3} \dfrac{22}{\cancel{7}} \times \cancel{6}^{^2} \times 6 \times \cancel{7}$

$\boxed{\boxed{\rm :\longmapsto V = 528 \ cm^3}}$