from a solid cylinder whose height is 12 centimetre and diameter 10 cm a conical cavity of same height and same diameter is hollowed out find volume and TSA of remaining solid
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Your answer is :-
Step-by-step explanation:
Volume of remaining solid = volume of cylinder - volume of cone.
r=5 cm (given)
h=12 cm
Volume of cylinder = πr2h
=3.14×52×12
=942cm2
Volume of cone = 31πr2h=31×3.14×52×12
=314cm3
Remaining volume = 942-314
=628cm3
Total surface of remaining solid = conical sutface area of cone + Area of circle + Cylindrical area of cylinder.
Conical sutface area of cone =πrr2+h2=204.203 cm2
Conical of cirle = πr2=78.54cm2
Cylindrical area of cylinder = 2πrh
=376.8cm2
Total surface area 659.543cm2
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