Question

from a solid cylinder whose height is 12cm and diameter is 10cm a conical cavity of same height and same diameter is hollowed out.find the volume and total surface and remaining solid​

Answer 1

Step-by-step explanation:

Volume of remaining solid = Volume of cylinder - Volume of Cone

In the given case,

r = 5cm

h = 12cm

Volume of Cylinder = pi * r * r * h = 3.14 * 5 * 5 * 12 = 942 cm^3

Volume of Cone = (1/3) * pi * r * r * h = (1/3) * 3.14 * 5 * 5 * 12 = 314 cm^3

Remaining Volume = 942 - 314 = 628cm^3

Total Surface of Remaining Solid = Conical surface area of Cone + Area of Circle + Cylindrical area of Cylinder

Conical surface area of Cone = pi * r * ((r^2 + h^2)^(1/2)) = 282.74cm^2

Area of Circle = pi * r * r = 78.54cm^2

Cylindrical area of Cylinder = 2 * pi * r * h = 376.8cm^2

Total Surface Area = 738.08cm^2

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