Question

From a solid cylinder whose height is 15 cm and diameter16 a conical cavity of the same height and same diameter is hollowed out.Find the total surface area of the remaining solid
$\pi = 3.14$
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Answer 1

answer is right
no mistakes
Mark as brainliest plz

Answer 2

Answer:

$527.52cm^2$

Step-by-step explanation:

Height of cylinder = 15 cm

Diameter of cylinder = 16 cm

Radius = $\frac{16}{2}$

Total surface area of cylinder = $2\pi r h + 2\pi r^2$

                                                 = $2 \times 3.14 \times (8)(15) + 2(3.14)(8)^2$

                                                 = $1155.52cm^2$

Height of cone = 15 cm

Diameter of cone = 16 cm

Radius = $\frac{16}{2}=8$

Total surface area of cone = $\pi r \sqrt{h^2+r^2}+\pi r^2$

                                             = $(3.14)(8) \sqrt{15^2+8^2}+(3.14)(8)^2$  

                                              = $628$  

The cone is hollowed out of cylinder

The total surface area of the remaining solid  = $1155.52-628$

                                                                           = $527.52cm^2$

Hence the total surface area of the remaining solid is  $527.52cm^2$