Question

from a solid cylinder whose height is 16 cm and radius is 12 CM a conical cavity of height 8 centimetre and base radius 6 cm is hollowed out find the volume of the total surface area of the remaining solid

Answer 1

Answer:

Step-by-step explanation:

given circle 

2x2 + 2y2 - 6x+8y+1=0  

dividing by 2 on both sides 

x^2+y^2-3x+4y+1/2=0

comparing with std form we get

2g=-3

g=-3/2

2f=4

f=2

r=root of g^2+f^2-c=root of 9/4+4-1/2=√23/2 units

center (-g,-f)=(3/2,-2)

let the radius of new circle be r which has double area

π r^2=2π *33/4

r=√23/2 units

center will be same as it is concetric (3/2,-2)

therefore new circle would be 

(x-3/2)^2+(y+2)^2=√((23/2) )^2

(x-3/2)^2+(y+2)^2=23/2