Question

from a solid cylinder whose height is 2.4 cm and diameter 1.4 CM a conical cavity of the same height and same diameter is hollowed out find the total surface area of the remaining solid to the nearest centimetre square​

Answer 1

Answer:

5.75cm^2

STEP BY STEP ANS

TSA OF CYLINDER=2πrh+2πr^2

[22÷7×2×7×24÷100+2×22÷7×7÷100]

=13.64

TSA OF CONE =7.89

REMAINING TSA =13.64-7.89 =5.75cm^2

hence proved