Question

from a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the
same height and same diameter is hollowed out. Find the total surface area of the
remaining solid to the nearest cm
​

Answer 1

Step-by-step explanation:

Given:

Height (h) of the conical part = Height (h) of the cylindrical part =2.4 cm

Diameter of the cylindrical part =1.4 cm

Answer 2

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Given,

Height of cylinder = 12–4 = 8 cm

Radius = 1.5 cm

Height of cone = 2 cm

Now, the total volume of the air contained will be = Volume of cylinder+2×(Volume of cone)

∴ Total volume = πr2h+[2×(⅓ πr2h )]

= 18 π+2(1.5 π)

= 66 cm3.