Question

From a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the same height and same diameter is hollowed out. Find the volume of remaining solid

Answer 1

Step-by-step explanation:

Given Data ( Cylinder)

h = 2.4 cm

d = 1.4 cm

So, radius r = d/2 = 1.4 / 2 = 0.7 cm

Given Data (Cone)

h = 2.4 cm

r = 1.4 cm

volume of Cylinder =

$\pi {r}^{2} h$

=

$\frac{22}{7} \times {0.7}^{2} \times 2.4$

= 3.696 cm³

volume of Cone =

$\frac{1}{3} \times \pi \times {r}^{2} \times h$

=

$\frac{1}{3} \times \frac{22}{7} \times {0.7}^{2} \times 2.4$

= 1.232 cm³

Net Volume left = Vol of Cylinder - Vol of Cone

= 3.696 - 1.232

= 2.464 cm³

Answer 2

Answer:

2.464 cm cube

Step-by-step explanation:

volume of cylinder = 3.696 cm cube ( according to formula)

volume of cone = 1.232 cm cube ( according to formula)

remaining solid = volume of cylinder - volume of cone

=3.696 - 1.232

= 2.464 cm cube

HOPE IT HELPS