Math, asked by Subhamlkr97, 1 year ago

from a solid cylinder whose height is 2.4 cm and diameter 1.4 cm conical cavity the same height and same diameter hollowed out find the total surface area of remaining solid

Answers

Answered by IshanS
60
Hi there!

Given,

Height of cylinder = Height of conical cavity, h = 2.4 cm

Diameter, d = 1.4 cm

Radius, r = 1.4/2= 0.7 cm

Slant height, l = √h² + r² = √(2.4)² + (0.7)² = √5.76 + 0.49 = √6.25 = 2.5 cm

TSA of the remaining solid = CSA of cylindrical part + CSA of conical part + Area of cylindrical base

TSA = 2πrh+ πrl+ πr²

= πr [ 2(h) + l + r ]

= 22/7 × 0.7 [ 2 × 2.4 + 2.5 + 0.7 ]

= 17.6 cm²

Hence,
TSA of remaining solid is = 17.6 cm²

[ Thank you! for asking the question. ]
Hope it helps!
Answered by krimusa7524
47

Hope it will be helpful to you

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