from a solid cylinder whose height is 2.4 cm and diameter 1.4 cm conical cavity the same height and same diameter hollowed out find the total surface area of remaining solid
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Answered by
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Hi there!
Given,
Height of cylinder = Height of conical cavity, h = 2.4 cm
Diameter, d = 1.4 cm
Radius, r = 1.4/2= 0.7 cm
Slant height, l = √h² + r² = √(2.4)² + (0.7)² = √5.76 + 0.49 = √6.25 = 2.5 cm
TSA of the remaining solid = CSA of cylindrical part + CSA of conical part + Area of cylindrical base
TSA = 2πrh+ πrl+ πr²
= πr [ 2(h) + l + r ]
= 22/7 × 0.7 [ 2 × 2.4 + 2.5 + 0.7 ]
= 17.6 cm²
Hence,
TSA of remaining solid is = 17.6 cm²
[ Thank you! for asking the question. ]
Hope it helps!
Given,
Height of cylinder = Height of conical cavity, h = 2.4 cm
Diameter, d = 1.4 cm
Radius, r = 1.4/2= 0.7 cm
Slant height, l = √h² + r² = √(2.4)² + (0.7)² = √5.76 + 0.49 = √6.25 = 2.5 cm
TSA of the remaining solid = CSA of cylindrical part + CSA of conical part + Area of cylindrical base
TSA = 2πrh+ πrl+ πr²
= πr [ 2(h) + l + r ]
= 22/7 × 0.7 [ 2 × 2.4 + 2.5 + 0.7 ]
= 17.6 cm²
Hence,
TSA of remaining solid is = 17.6 cm²
[ Thank you! for asking the question. ]
Hope it helps!
Answered by
47
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