From a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of
the same height and same diameter is hollowed out. Find the total surface area of the
remaining solid to the nearest cm
2
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total surface of area = csa of cylinder + area of circle + csa of cone
slant height = h Ka squire + r Ka square
214/10 + 07/10 squre
576/100 + 49/100
625 /100
root 25 / 10 Ka whole squre .
25/10
2.5 .
2 ×22/7 ×7/10 ×2.4 + 22/7 × 7/10×7/10 +22/7×7/10×25/10
common 22(2×24/10 +7/10+25/10
22(4.8/10 +0.7/10 +2.5/10 )
22(8.0/10 )
22×4/5
28/5
17.6 approximately
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