Question

From a solid cylinder whose height is 2.4 cm diameter is 1.4 cm, a conical cavity of the same height and same diameter is hollowed out. Find the volume of the remaining solid to the nearest cm3.[Use ,pie = 22/7

Answer 1

HERE IS YOUR ANSWER :-

Hi there!

Given,

Height of cylinder = Height of conical cavity, h = 2.4 cm

Diameter, d = 1.4 cm

Radius, r = 1.4/2= 0.7 cm

Slant height, l = √h² + r² = √(2.4)² + (0.7)² = √5.76 + 0.49 = √6.25 = 2.5 cm

TSA of the remaining solid = CSA of cylindrical part + CSA of conical part + Area of cylindrical base

TSA = 2πrh+ πrl+ πr²

= πr [ 2(h) + l + r ]

= 22/7 × 0.7 [ 2 × 2.4 + 2.5 + 0.7 ]

= 17.6 cm²

Hence,

TSA of remaining solid is = 17.6 cm²

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Answer 2

Answer:

Step-by-step explanation: