Question

from a solid cylinder whose height is 6cm and diameter 5cm a conical cavity of the same height and same diameter is hollowed out.find the TSA of the remaining solid​

Answer 1

Volume of remaining solid = volume of cylinder - volume of cone.

r=5 cm (given)

h=12 cm

Volume of cylinder = πr

2

h

=3.14×5

2

×12

=942cm

2

Volume of cone =

3

1

πr

2

h=

3

1

×3.14×5

2

×12

=314cm

3

Remaining volume = 942-314

=628cm

3

Total surface of remaining solid = conical sutface area of cone + Area of circle + Cylindrical area of cylinder.

Conical sutface area of cone =πr

r

2

+h

2

=204.203 cm

2

Conical of cirle = πr

2

=78.54cm

2

Cylindrical area of cylinder = 2πrh

=376.8cm

2

Total surface area 659.543cm

2