Question

From a solid cylinder, whose height is 8cm and radius is 6cm, a conical cavity of height 8cm and of base radius 6cm is hollowed out. Find the volume of the remaining solid. Also find the total surface area of the remaining solid.

Answer 1

Volume of the solid cylinder = $\pi r^{2} h$ = 3.14 X $6^{2}$ X 8
= 3.14 X 36 X 8
= 904.32 $cm^{3}$
Volume of the conical cavity = $\frac{1}{3} \pi r^{2}h$ 
= $\frac{1}{3}$ X 3.14 X $6^{2}$ X 8
= $\frac{1}{3}$ X 3.14 X 36 X 8
= 301.44 $cm^{3}$
Volume of resulting solid = Volume of cylinder- Volume of conical cavity.
= 904.32 - 301.44 = 602.88 $cm^{3}$

Answer 2

Answer:

I have only given the answer for Total surface area as it was not given in other answers .

Hope it helps

;-) RD