Question

From a solid cylinder whose height is2.4 cm n diameter 1.4cm,a conical cavity of the same height n sme diameter is halloowed out.find the total surface area of the remaining solid to the nearest cm"2​

Answer 1

≡QUESTION≡

From a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the  same height and same diameter is hollowed out. Find the total surface area of the  remaining solid to the nearest cm²

║⊕ANSWER⊕║

GIVEN

Height of cylinder = height of conical cavity = 2.4 cm

Diameter = 1.4 cm

Radius = 1.4/2= 0.7 cm

TSA of the remaining solid = CSA of cylindrical part + CSA of conical part +                                    Area of cylindrical base

= 2πrh+ πrl+ πr²

= (2 * 3.14 * 0.7 * 2.4) +( 3.14 * 0.7 * 2.4) + (3.14 * 0.7 * 0.7)

= 17.6 cm²