From a solid cylinders whose height is 3.6cm and diameter is 2.1 cm,a conical cavity of the same height and same diameter is hooolowed out .find the total surface area of the remaining solid to the nearest cm2
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Answer:
By using
2πrh+πr²+πrl
πr(2h+r+l)
22/7×2.1/2(2×3.6+2.1/2+7.5/2)...........here you can find 'l' by using r²+h²=l²
Step-by-step explanation:
=3.3(7.2+2.1/2+7.5/2)
=3.3×24/2
=3.3×12
=39.6cm²
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