From a solid right circular cylinder with height 10 cm and radius of the base 6 cm, a right circular cone of the same height and base is removed Find the volume of the remaining solid. (Taken=3.14.)
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Answer:
Volume of remaining solid=(πr
2
h)−
3
1
πr
2
h
={π×6
2
×10−
3
1
×π×6
2
×10}cm
3
=(360π−120π)cm
3
=240πcm
3
slant height of the cone
=OC=
OC
2
+O
′
C
2
=
10
2
+6
2
=2
34
cm
Whole surface area = curved surface area of the cylinder + area of the base the cylinder + curved surface area of cone
={2π×6×10+π×6
2
+π×6×2
34
}cm
2
=(156+12
34
)πcm
2
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